Wow, what a lineup!
The top 3 smartest contestants ever on Jeopardy will go head to head in the Greatest of All Time Tournament on ABC.
Winner gets $1 million dollars.
Who will become the Jeo-GOAT?
“Based on their previous performances, these three are already the ‘greatest,’ but you can’t help wondering: Who is the best of the best?” Alex Trebek said.
“Jeopardy! The Greatest of All Time” will air as follows:
· TUESDAY, JANUARY 7 (8-9 p.m. EST)
· WEDNESDAY, JANUARY 8 (8-9 p.m. EST)
· THURSDAY, JANUARY 9 (8-9 p.m. EST)
· *FRIDAY, JANUARY 10 (8-9 p.m. EST)
· *TUESDAY, JANUARY 14 (8-9 p.m. EST)
· *WEDNESDAY, JANUARY 15 (8-9 p.m. EST)
· *THURSDAY, JANUARY 16 (8-9 p.m. EST)
Meet the competitors:
Ken Jennings became a household name during his record 74-game winning streak, the longest in Jeopardy! history. His winnings total $3,370,700.
Brad Rutter is the highest money winner of all time across any television game show, with total Jeopardy! winnings of $4,688,436. He has never lost Jeopardy! to a human opponent.
James Holzhauer holds the record for all 15 of the top Single-Game Winnings records on Jeopardy!, and he just won the 2019 Tournament of Champions. His winnings total $2,712,216.
What: Jeopardy’s Greatest of All Time Tournament
When: January 7-16, 2020
Time: 8:00 p.m. – 9:00 p.m.